www.mjjq.net > 质量为0.3千克的铝锅中放有2千克的水,把它们从20...

质量为0.3千克的铝锅中放有2千克的水,把它们从20...

(1)铝锅吸收的热量:Q铝=c铝m铝(t-t0)=0.88×103J/(kg?℃)×0.3kg×(80℃-20℃)=1.584×l04J,(2)水吸收的热量:Q水=c水m水(t-t0)=4.2×103J/(kg?℃)×2kg×(80℃-20℃)=5.04×l05J,(3)铝锅和水一共需要吸收的热量:Q=Q铝+Q水=1.584×l04J+5...

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